The centre of mass of system of particles does not depend on

Look at the drawing given in the figure which has been drawn with ink of uniform line-thickness. The mass of ink used to draw each of the two inner circles, and each of the two line segments is $m$. The mass of the ink used to draw the outer circle is $6 \mathrm{~m}$. The coordinates of the centres of the different parts are: outer circle $(0,0)$, left inner circle $(-a, a)$, right inner circle $(a, a)$, vertical line $(0,0)$ and horizontal line $(0,-a)$. The $y$-coordinate of the centre of mass of the ink in this drawing is

A spherical hollow is made in a lead sphere of radius $R,$ such that its surface touches the outside surface of lead sphere and passes through the centre. What is the shift in the centre of mass of lead sphere due to the following ?

Four bodies of masses $2, 3, 5$ and $8\,kg$ are placed at the four corners of a square of side $2\,m$ as shown. The position of $CM$ will be

Two masses $M$ and $m$ are attached to a vertical axis by weightless threads of combined length $l$. They are set in rotational motion in a horizontal plane about this axis with constant angular velocity $\omega $. If the tensions in the threads are the same during motion, the distance of $M$ from the axis is

From a circular disc of radius $R$ a triangular portion is cut (see fig.). The distance of  $COM$ of the remaining disc from centre of disc $O$ is:-